2x^2+240x-81000=0

Solution for 2x^2+240x-81000=0 equation:

2x^2+240x-81000=0

a = 2; b = 240; c = -81000;
Δ = b2-4ac
Δ = 2402-4·2·(-81000)
Δ = 705600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{705600}=840$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-840}{2*2}=\frac{-1080}{4}
=-270
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+840}{2*2}=\frac{600}{4}
=150
$